Print a double(> than 17 digits) value without E notaion in Java -

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i have requirement of printing 22 digit number, when print it, jvm using e notation. have tried bigdecimal class, printf(), string.format(), didn't succeed. accurate till 17 digits, 18th digit data manipulated. example:

original number : 2333333333333333333333 output: 2333333333333333456252

here fragment of code. hope helps

double[] n = new double[t]; for(int i=0;i<t;i++){         n[i] = double.parsedouble(scn.next());     } if(........){ system.out.println(new bigdecimal(n[i]).toplainstring()); system.out.printf("%.0f ", n[i]); }

you're passing in double constructor of bigdecimal causing precision lost. use

system.out.println(new bigdecimal(scn.next()).toplainstring());

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