sorting - Find the two largest numbers passed on the stack and multiply them, return DX:AX pair -

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i have assignment passed 4 values on stack (v1, v2, v3, v4), find 2 largest values out of four, , multiply them return dx:ax pair.

this code have come far, comparing values 1 , storing highest value in ax , second highest value in bx. problem code hangs when tested in dosbox, , i'm not sure causing it.

edit: finished , working!

;--------------------------------------- ; ; code segment ; ;--------------------------------------- _linkhll:       push bp     ; saves caller's bp     mov bp,sp   ; loads bp sp                          mov ax,[bp+4] ;load v1 ax       mov bx,[bp+6] ;load v2 bx ;--------------------------------------- ; find first largest number ;---------------------------------------     cmp ax,bx        ;compare value 1 , 2       je doubles       cmp ax,bx       ja  l2        ;ax > bx, goto l2       mov ax,bx     ;make v2 largest number     l2:mov bx,[bp+8] ;load v3 bx       cmp ax,bx     ;compare value ax , v3       je doubles       cmp ax,bx       ja  l3        ;ax > bx, goto l3       mov ax,bx     ;make v3 largest number     l3:mov bx,[bp+10]    ;load v3 bx       cmp ax,bx     ;compare value ax , v4       je doubles       ja  s1        ;ax > bx, goto l3       mov ax,bx     ;make v4 largest number       jmp s1  doubles:       mov cx,[bp+8] ;mov v3 cx       cmp ax,cx     ; bx > cx       ja  v4bigger  ; yes, skip v4 test       mov ax,cx     ;if no, make cx new ax v4bigger:       mov cx,[bp+10]    ;v4 cx        cmp bx,cx     ;compare current highest       ja mult           mov bx,cx       jmp mult     ;--------------------------------------- ; find second largest number ;---------------------------------------     s1:mov bx,[bp+4] ;load v1 bx       mov cx,[bp+6] ;load v2 cx       cmp ax,bx     ;compare value ax , v1       je  v2mov     ;ax = bx, multiply them       cmp ax,cx     ;compare value ax , v2       je  s2        ;ax = cx, mov cx bx , multiply       cmp bx,cx     ;compare v1 , v2       ja  s2        ;bx > cx goto s2 v2mov:       mov bx,cx     ; make v2 current second highest     s2:mov cx,[bp+8] ;load v3 cx       cmp ax,cx     ;compare value ax , v3       je  s3        ;ax = cx, goto s3       cmp bx,cx     ;compare ax , v3       ja  s3        ;bx > cx goto s3 v3mov:       mov bx,cx     ;mov v3  2nd highest number spot     s3:mov cx,[bp+10]    ;load v4 cx       cmp ax,cx     ;compare value ax , v4       je  mult      ;ax = cx, goto s3 // mult????       cmp bx,cx     ;compare ax , v3       ja  mult      ;bx > cx goto s3 v4mov:       mov bx,cx     ;make v4 second highest number  mult:       mul bx        ;multiply ax bx        pop bp                                  ;                                        ;                                        ;          ret                           ;                                        ;          end                           ; ;---------------------------------------

you're pushing bp on stack @ start of function. don't pop off stack before returning. hence, when ret instruction executes , tries return address off stack gets old value of bp instead.


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