python - NameError: name 'argv' is not defined -

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i trying make google api call , getting error beginning of code found here:

import os  import argparse import sys  apiclient import sample_tools oauth2client import client  # declare command-line flags. argparser = argparse.argumentparser(add_help=false) argparser.add_argument(     'profile_id', type=int,     help='the id of profile campaigns for')      # authenticate , construct service. service, flags = sample_tools.init(     argv[1:], 'dfareporting', 'v2.1', __doc__, os.path.abspath(os.path.dirname("__file__")), parents=[argparser],     scope=['https://www.googleapis.com/auth/dfareporting',            'https://www.googleapis.com/auth/dfatrafficking'])  if __name__ == '__main__':   main(sys.argv)

however, sample_tools.init function not returning service , flags object. think have isolated argv argument a

nameerror: name 'argv' not defined

any appreciated!!!

you missing sys:

sys.argv[1:]

you either need from sys import argv , use argv everywhere or import sys have , use sys.argv. don't see main function anywhere main(sys.argv) going cause nameerror


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