What is the difference when calling subroutine with and without & in Perl? -

for homework, told make subroutine within perl, , when called arguments in it, print arguments. did , second part of homework call first subroutine within second one. did this, question was: try running second subroutine "&" while calling first one, , without , write difference in these 2 different calls. subroutine seems works in both cases, , without, don't know changed, therefore don't know write. off topic, code fine? kinda first time coding in perl.

this code:

#!/usr/bin/perl  use 5.010; use strict; use warnings;  show_args('fred','barney','betty');  show_args_again();  sub show_args{     ($broj1, $broj2, $broj3) = @_;     print "the arguments are: " . "$broj1, " . "$broj2, " . "$broj3.\n"; } sub show_args_again{     &show_args('fred','barney','betty'); } 

does assignment whether show_args_again should called parameters?

the thing can think of meant discover demonstrated code. give try

#!/usr/bin/perl  use 5.010; use strict; use warnings;  show_args('fred', 'barney', 'betty'); print "---\n"; show_args_again('fred', 'barney', 'betty');  sub show_args{     ($broj1, $broj2, $broj3) = @_;     no warnings 'uninitialized';     print "the arguments are: $broj1, $broj2, $broj3.\n"; }  sub show_args_again {     show_args(@_);     &show_args(@_);     show_args();     &show_args();     show_args;     &show_args; }