excel - VBA, 'Left' Different Strings Dynamically -

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having trouble shortening strings in column making dynamic directory. ex: 3 strings in column, 1 string may continue 10 rows, string 20 rows, , 15 rows. each needing shorted different amount

specifically: had several words either sepearated -, _ , +. example 1 sheet has pv01_52352, pv+50, pv-100, irvega_242422, irvega word works. pv's struggling with. desired results works before special characters, pv01, pv , irvega desired result .

how can use left or anyway shorten these all? quite hard me since 1 string ill need first 4 characters, 5 characters shortened , need done throughout workbook.

any input appreciated, thanks.

i've found determining ascii character number code function (using upper function reduce possibilities) produces satisfactory results.

        truncate @ first non-alphabetic character

the array formula in b2 strictly alphabetic characters is,

=left(a2, min(row(indirect("1:"&len(a2)))+((code(mid(upper(a2), row(indirect("1:"&len(a2))), 1))>64)*(code(mid(upper(a2), row(indirect("1:"&len(a2))), 1))<91))*1e+99)-1)

an array formula in b2 alphanumeric characters is,

=left(a2, min(row(indirect("1:"&len(a2)))+(((code(mid(upper(a2), row(indirect("1:"&len(a2))), 1))>64)*(code(mid(upper(a2), row(indirect("1:"&len(a2))), 1))<91))+((code(mid(a2, row(indirect("1:"&len(a2))), 1))>47)*(code(mid(a2, row(indirect("1:"&len(a2))), 1))<58)))*1e+99)-1)

array formulas need finalized ctrl+shift+enter↵.

a vba user defined function (aka udf) strictly alphabetic characters be,

function just_the_alpha(str string)     dim tmp string, c long     c = 1 len(str)         if asc(mid(ucase(str), c)) > 64 , _            asc(mid(ucase(str), c)) < 91             tmp = tmp & mid(str, c, 1)         else             exit         end if     next c     just_the_alpha = tmp end function

a vba udf alphanumeric characters be,

function just_the_alphanum(str string)     dim tmp string, c long     c = 1 len(str)         if (asc(mid(ucase(str), c)) > 64 , _             asc(mid(ucase(str), c)) < 91) or _            (asc(mid(str, c)) > 47 , _             asc(mid(str, c)) < 58)             tmp = tmp & mid(str, c, 1)         else             exit         end if     next c     just_the_alphanum = tmp end function

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