c++ - Select three choices (multiple choices) in C -

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hi working on calculator , have choices on solve. first, asked how many given have. code, made 3 given. default, input 3. next, have list of 11 given in order solve equations. user chose 3 numbers 1-11... have started case using number 1,3,9 , 1,3,10, , 1,3,11. problem when choose 1,3,10 randomly, example change order in input in choice,choice2,choice 3 choosing 3,10,1 instead of 1,3,10...

so let's choose 1,3,10 inputted in order... 10,3,1.. still must go action implement.

i used following line if statement... if(choice==1,3,10 && choice2==1,3,10 &7 choice3==1,3,10) execute action...

and

if( (choice== 1 || 3 || 10) && (choice2== 1 || 3 || 10) && (choice3== 1 || 3 || 10)) execute action...

i've tried above won't execute statements below it... execute 1 above...

#include<stdio.h> #include<conio.h> #include<math.h> #define pi 3.14159265  int main(){  double length, angle, radius, tangent, chord, midordinate, external, degree; double pcurve,ptan,pintersect; double ulength, udegree, uangle, uradius, utangent, uchord, umidordinate, uexternal; int choice, choice2, choice3, given;  //for sin, cos, tan double x, ret, val; val = pi / 180;  printf("enter number of given: "); scanf("%d",&given);  if(given==3){         choice:         printf("[1]   -  angle\n");         printf("[2]   -  degree\n");          printf("[3]   -  radius\n");         printf("[4]   -  length of curve\n");                    printf("[5]   -  tangent\n");         printf("[6]   -  chord\n");         printf("[7]   -  midordinate\n");         printf("[8]   -  external distance\n");          printf("[9]   -  point of intersection\n");         printf("[10]  -  point of curve\n");         printf("[11]  -  point of tangent\n");  printf("\n");  printf("enter 1st given: "); scanf("%d",&choice);  printf("enter 2nd given: "); scanf("%d",&choice2);     printf("enter 3rd given: "); scanf("%d",&choice3);  printf("\n-----------------------------------\n");  if(choice==1,3,9 && choice2==1,3,9 && choice3==1,3,9){         printf("enter angle: ");         scanf("%lf",&angle);          printf("enter radius: ");         scanf("%lf",&radius);          printf("enter point of intersection (point of curve value): ");         scanf("%lf",&pcurve);          printf("enter point of intersection (tangent value): ");         scanf("%lf",&tangent);          printf("-----------------------------------\n");         printf("\ngiven:\n");         printf("-----------------------------------\n");         printf("angle = %lf\n",angle);         printf("radius = %lf\n",radius);         printf("point of intersection (pi) = %lf + %lf\n", pcurve,tangent);          uangle = angle/2;          printf("-----------------------------------\n");         printf("\nresults:\n");         printf("-----------------------------------\n");         length=(radius*angle*pi)/180;         tangent = radius * (tan(uangle*val));         chord = 2*radius*(sin(uangle*val));          midordinate = radius - (radius*(cos(uangle*val)));         external = radius *( (1/(cos (uangle*val) ) ) - 1 ) ;            pintersect = pcurve + tangent;         pcurve = pintersect - tangent;         ptan = pcurve + length;          printf("radius = %lf\n",radius);         printf("length of curve = %lf\n",length);         printf("tangent = %lf\n",tangent);         printf("chord = %lf\n",chord);         printf("mid ordinate = %lf\n",midordinate);         printf("external distance = %lf\n",external);         printf("point of intersection = %lf\n",pintersect);         printf("point of curve = %lf\n",pcurve);         printf("point of tangent = %lf\n",ptan);  }  else  if( (choice== 1 || 3 || 10) && (choice2== 1 || 3 || 10) && (choice3== 1 || 3 || 10)){         printf("enter angle: ");         scanf("%lf",&angle);          printf("enter radius: ");         scanf("%lf",&radius);          printf("enter point of curve (point of intersection value): ");         scanf("%lf",&pintersect);          printf("enter point of curve (tangent value): ");         scanf("%lf",&tangent);          printf("-----------------------------------\n");         printf("\ngiven:\n");         printf("-----------------------------------\n");         printf("angle = %lf\n",angle);         printf("radius = %lf\n",radius);         printf("point of curve (pc) = %lf - %lf\n", pintersect,tangent);          uangle = angle/2;          printf("-----------------------------------\n");         printf("\nresults:\n");         printf("-----------------------------------\n");         length=(radius*angle*pi)/180;         tangent = radius * (tan(uangle*val));         chord = 2*radius*(sin(uangle*val));          midordinate = radius - (radius*(cos(uangle*val)));         external = radius *( (1/(cos (uangle*val) ) ) - 1 ) ;            pintersect = pcurve + tangent;         pcurve = pintersect - tangent;         ptan = pcurve + length;          printf("radius = %lf\n",radius);         printf("length of curve = %lf\n",length);         printf("tangent = %lf\n",tangent);         printf("chord = %lf\n",chord);         printf("mid ordinate = %lf\n",midordinate);         printf("external distance = %lf\n",external);         printf("point of intersection = %lf\n",pintersect);         printf("point of curve = %lf\n",pcurve);         printf("point of tangent = %lf\n",ptan);  }  if(choice==1,3,11 && choice2==1,3,11 && choice3==1,3,11){         printf("enter angle: ");         scanf("%lf",&angle);          printf("enter radius: ");         scanf("%lf",&radius);          printf("enter point of tangent (point of curve value): ");         scanf("%lf",&pintersect);          printf("enter point of tangent (length value): ");         scanf("%lf",&length);          printf("-----------------------------------\n");         printf("\ngiven:\n");         printf("-----------------------------------\n");         printf("angle = %lf\n",angle);         printf("radius = %lf\n",radius);         printf("point of curve (pc) = %lf + %lf\n", pcurve,length);          uangle = angle/2;          printf("-----------------------------------\n");         printf("\nresults:\n");         printf("-----------------------------------\n");         length=(radius*angle*pi)/180;         tangent = radius * (tan(uangle*val));         chord = 2*radius*(sin(uangle*val));          midordinate = radius - (radius*(cos(uangle*val)));         external = radius *( (1/(cos (uangle*val) ) ) - 1 ) ;            pintersect = pcurve + tangent;         pcurve = pintersect - tangent;         ptan = pcurve + length;          printf("radius = %lf\n",radius);         printf("length of curve = %lf\n",length);         printf("tangent = %lf\n",tangent);         printf("chord = %lf\n",chord);         printf("mid ordinate = %lf\n",midordinate);         printf("external distance = %lf\n",external);         printf("point of intersection = %lf\n",pintersect);         printf("point of curve = %lf\n",pcurve);         printf("point of tangent = %lf\n",ptan);  }     }   getch(); return 0; } 

if(choice==1,3,9 && choice2==1,3,9 && choice3==1,3,9){  if( (choice== 1 || 3 || 10) && (choice2== 1 || 3 || 10) && (choice3== 1 || 3 || 10))  //always true  if(choice==1,3,11 && choice2==1,3,11 && choice3==1,3,11){

do consider these conditions valid syntax behave needs ?

correct 

if((choice==1 ||choice==3 ||choice==9) && (choice2==1 ||choice2==3 ||choice2==9) && (choice3==1 ||choice3==3 ||choice3==9))  if((choice==1 ||choice==3 ||choice==10) && (choice2==1 ||choice2==3 ||choice2==10) && (choice3==1 ||choice3==3 ||choice3==10))  if((choice==1 ||choice==3 ||choice==11) && (choice2==1 ||choice2==3 ||choice2==11) && (choice3==1 ||choice3==3 ||choice3==11))

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