bash - Why is a shell script giving syntax errors when the same code works elsewhere? -

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this question has answer here:

i have simple shell script copied working script. works if copy-paste terminal:

if true   true fi

however, when run script bash myscript, various syntax errors if of keywords missing.

  • myscript: line 4: syntax error near unexpected token `fi' , if then isn't there.
  • myscript: line 6: syntax error: unexpected end of file , if fi isn't there.
  • myscript: line 4: syntax error near unexpected token `$'\r' .. what?

why happen in particular script, not on command line or in script copied from?

tl;dr: script has windows style crlf line endings, aka \r\n.

convert unix style \n deleting carriage returns.

how check if script has carriage returns?

they're detectable ^m in output of cat -v yourscript:

$ cat -v myscript if true^m then^m   true^m ...

how remove them?

set editor save file unix line endings, aka "line terminators" or "end-of-line characters", , resave it.

you can remove them command line dos2unix yourscript or cat yourscript | tr -d '\r' > fixedscript.

why carriage returns cause syntax errors?

the carriage return character character bash. then not same then\r, bash doesn't recognize keyword , assumes it's command. keeps looking then , fails

if there happens trailing space after then, similar problem fi.


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